Balance the equation for the reaction of sodium hydroxide with sulphuric acid.

H2SO4 + NaOH --> Na2SO4 + H2OWrite out all the elements involved, and how many times they appear on each side.H 3:2,S 1:1,O 5:5,Na 1:2.Start by making the number of sodiums the same on both sides by putting a 2 in front of NaOH:H2SO4 + 2NaOH --> Na2SO4 + H2O.H 4:2,S 1:1,O 6:5,Na 2:2.Then make the number of hydrogens equal on both sides by putting a 2 in front of H2O:H2SO4 + 2NaOH --> Na2SO4 + 2H2O.This makes the number of oxygens equal as well, so the equation has now been balanced.

Answered by Louise B. Chemistry tutor

10729 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

How does sodium chloride (salt/grit) lower the freezing point of water?


Why is chlorine more reactive than iodine? (3 marks)


Explain which species is oxidised in this reaction: Br2 +2I– 2Br– +I2.


Zinc reacts with dilute Hydrochloric acid, what is the chemical equation for this reaction? what would you see? How could you speed up this reaction?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences