Balance the equation for the reaction of sodium hydroxide with sulphuric acid.

H2SO4 + NaOH --> Na2SO4 + H2OWrite out all the elements involved, and how many times they appear on each side.H 3:2,S 1:1,O 5:5,Na 1:2.Start by making the number of sodiums the same on both sides by putting a 2 in front of NaOH:H2SO4 + 2NaOH --> Na2SO4 + H2O.H 4:2,S 1:1,O 6:5,Na 2:2.Then make the number of hydrogens equal on both sides by putting a 2 in front of H2O:H2SO4 + 2NaOH --> Na2SO4 + 2H2O.This makes the number of oxygens equal as well, so the equation has now been balanced.

Answered by Louise B. Chemistry tutor

10406 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Describe the effects of increasing the 1)Pressure 2) Temperature of the following system and what effect this will have on the equilibrium position of this reversible reaction given the forward reaction is exothermic 3H2 + N2 <--> 2NH3


Why can Diesel be separated from crude oil using fractional distillation?


Why is chlorine more reactive than iodine?


How does paper chromatography work?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences