Balance the equation for the reaction of sodium hydroxide with sulphuric acid.

H2SO4 + NaOH --> Na2SO4 + H2OWrite out all the elements involved, and how many times they appear on each side.H 3:2,S 1:1,O 5:5,Na 1:2.Start by making the number of sodiums the same on both sides by putting a 2 in front of NaOH:H2SO4 + 2NaOH --> Na2SO4 + H2O.H 4:2,S 1:1,O 6:5,Na 2:2.Then make the number of hydrogens equal on both sides by putting a 2 in front of H2O:H2SO4 + 2NaOH --> Na2SO4 + 2H2O.This makes the number of oxygens equal as well, so the equation has now been balanced.

LB
Answered by Louise B. Chemistry tutor

13021 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Describe the difference between ionic, covalent, and metallic bonding.


Describe one chemical test and one physical test for pure water.


What are the differences between intermolecular and intramolecular forces?


Describe a single covalent bond in terms of the electron distribution of the atoms involved.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning