Solve the simultaneous equations: 4x+5y=13 and 3x-2y=27


Equation 1 is 4x+5y=13 - multiply it by 3, Equation 2 is 3x-2y=27 - multiply it by 4, New equation 1 is 12x+15y=39, New equation 2 is 12x-8y=108, Subtract new equation 2 from new equation 1 - 23y=-69 therefore y=-3, Substitute y=-3 into equation 1 - 4x+(5x-3)=13, 4x-15=13, 4x=28, x=7. Final answer: x=7, y=-3

TD
Answered by Thea D. Maths tutor

3804 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise the expression: 8x + 32


Show that ((√ 18 + √ 2)^2)/(√8 - 2) can be written in the form a(b + 2) where a and b are integers.


Find the points where f(x)=x^2-5x-14 meets the x-axis and find the turning point


An isosceles triangle has a base with length x+4 and the other two sides have length x+3. The perimeter of this isosceles triangle is 16cm. Find the area of the triangle.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences