Integrate 2x^5 + 7x^3 - (3/x^2)
Integrating xn gives you xn+1/(n+1).Integral of 2x5 is 2x6/6 = x6/3. The integral of 7x3 is 7x4/4.-(3/x2) can be rewritten as -3x-2. Therefore the integral is -3x-1/-1 = 3x-1 = 3/x. As it is an indefinite integral there is also a constant of integration c.Answer: (x6/3) + (7x4/4) + (3/x) + c
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