A pipe has one open and one closed end. Determine the ratio of the frequency of the first harmomic to that of the next harmonic.
The first harmonic has wavelength λ1 = 4L and the next harmonic has wavelength λ2 = 4L/3. Hence :f1/f2 = (4L/3)/4L = 1/3
The first harmonic has wavelength λ1 = 4L and the next harmonic has wavelength λ2 = 4L/3. Hence :f1/f2 = (4L/3)/4L = 1/3
