Solve the simultaneous equations 3x + y = –4 and 3x – 4y = 6

  1. Label first equation as equation 1 and the second as equation 22) Make y the subject of the equation from equation (1); hence: eq 1 : y = -4 -3x3) Substitute the new equation into equation (2) : 3x- 4(-4-3x)=6 --> 3x+12x +16=64) Collect like terms : 15x = -10, so x = -2/3 5) Substitute calculated value of x into any of the original equations to find y, hence y= -2
MI

Related Maths GCSE answers

All answers ▸

Solve 6x-5 > 4x+13


Simplify 3/(x+1) + (3x-9)/2 = 1, to get a quadratic equation in the format ax^2 + bx + c = 0.


Factorise: x^2+2x-3


Simplify (2^2)^3