Solve the simultaneous equations 3x + y = –4 and 3x – 4y = 6

  1. Label first equation as equation 1 and the second as equation 22) Make y the subject of the equation from equation (1); hence: eq 1 : y = -4 -3x3) Substitute the new equation into equation (2) : 3x- 4(-4-3x)=6 --> 3x+12x +16=64) Collect like terms : 15x = -10, so x = -2/3 5) Substitute calculated value of x into any of the original equations to find y, hence y= -2
Answered by Munachi I. Maths tutor

2353 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following fractional quadratic equation 14/(x^2-9)+1/(3-x)+(4-x)/(x+3)=7/(x+3), assuming x=/=+-3.


How do you solve algebraic fractions with quadratics?


The diameter of a ring is 19mm. Calculate the area of the ring in cm^2, giving the area to 3 significant figures.


How can I use the Pythagoras' Theorem to work out the length of a missing side of a triangle?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences