solve y=3x+4, x=y+1

Equation 1) y=3x+4Equation 2) y=x+1
Rearrange equation 2 into terms of x as this is the simplest: x= y-1 (We do this by subtracting 1 off of each side to get X by itself)Substitute new equation 2 into 1: y=3(y-1)+4Expand the bracket by separately multiplying the factors inside the bracket by the value in front: y=3y-3+4Collect like terms: -1=2y (we do this by collecting the y's on the side where they will be positive and the single numbers on the other side and add together)Now we can solve y=-1/2 (we do this by dividing each side by 2 to get y on its own)Now we can substitute this value back into equation 2 to get: -1/2=x+1Subtract 1 off of each side to get -3/2 = x

Answered by Caitlin S. Maths tutor

2660 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

In integration, what does the +c mean and why does it disappear if you have limits?


a right-angled triangle has base 2x + 1, height h and hypotenuse 3x. show that h^2 = 5x^2 - 4x - 1


How do I solve the following simultaneous equations? y = 2x -3 and 2x + 3y = 23


Simplify fully 3(3 – x) – 2(x – 4)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences