What is the pH of a 25 ml sample of 0.2 M sulfuric acid? What is the pH after 5 ml of 0.25 M sodium hydroxide is added?

H2SO4 fully dissociates into ions (strong acid). It is diprotic therefore concentration of H+ ions is twice that of the acid = 0.4 M. pH = -log[H+] = -log[0.4] = 0.3979... = 0.40 to 2 d.pOH- ions react with H+ ions to produce water. Therefore (moles of H+) - (moles of OH+) = (moles of H+ remaining in solution).= 5 x 10-3 moles (of H+) - 1.25 x 10-3 moles (of OH-) = 3.75 x 10-3 moles remaining.Conc. of H+ = n/V = 0.125 M. pH = -log[0.125] = 0.90 to 2 d.p

GR
Answered by George R. Chemistry tutor

3071 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Why is ethylamine a stronger base than phenylamine?


What is the difference between an ionic and covalant bond?


Given the following equilibrium: H2O + H2O <-> H3O+ + OH- and the Kw = 10^-14, determine the concentration of OH- species after the addition of 1 mmol of HCl to 1 L of neutral water.


How do you calculate the equilibrium constant, Kc, of a reaction?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences