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Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

Begin by collecting log_2 terms.log_2(3x + 7) - log_2(x – 1) + = 3 Using the rule of log terms we getlog_2((3x+7)/(x-1)) = 3 (3x+7)/(x-1) = 2³3x+7 = 8(x-1)3x+7-8x+8 = 0 -5x+15 = 0 x= 3

Answered by Catriona F. • Maths tutor

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Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

Related Maths Scottish Highers answers

Given f(x) = (x^(2)+(3x)+1)/(x^(2)+(5x)+8), find f'(x) and simplify your answer.

Find the stationery points of x^3 + 3x^2 - 24x + 7 and determine whether the slope is increasing or decreasing at x=3.

log_a(36) - log_a(4) = 0.5, what is a?

Integrate lnx with respect to x

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Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.

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Given f(x) = (x^(2)+(3*x)+1)/(x^(2)+(5*x)+8), find f'(x) and simplify your answer.

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log_a(36) - log_a(4) = 0.5, what is a?

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We're here to help

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© MyTutorWeb Ltd 2013–2025

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Given f(x) = (x^(2)+(3x)+1)/(x^(2)+(5x)+8), find f'(x) and simplify your answer.