An electron is moving with speed 2x10^5ms-1 through a magnetic field of strength 0.5T. If the electrons velocity is perpendicular to the direction of the magnetic field, what is the magnitude of the force felt by the electron?

F = qv x B = qvB sin(O). q is the electrons charge = 1.6x10-19 C. v is the electrons speed = 2x105 ms-1 . B is the magnetic field strength = 0.5 T. O is the angle between the electrons velocity vector and the magnetic field vector. Velocity is perpendicular to field so O = 90 degrees, sin(90)=1 therefore: F=qvB. Plugging the values into the equation we have :F= 1.6x10-19 x 2x105 x 0.5 Cms-1 T Therefore F=1.6x10-14 N

AB
Answered by Angus B. Physics tutor

2000 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

why is gravitational potential negative?


State what is meant by resonance and provide some examples where it is crucial.


A uniform plank of wood of mass 32 kg and length 4.0 m is used to cross a ditch. In the ditch is a rock, which is used to support the plank horizontally 0.80 m from one end. The other end is supported by the bank. Calculate the rock's supporting force.


A motorist traveling at 10m/s, was able to bring his car to rest in a distance of 10m. If he had been traveling at 30m/s, in what distance could he bring his cart to rest using the same breaking force?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning