Solve x^2 = 4(x – 3)^2

x2 = 4(x-3)2x2 = 4(x-3)(x-3) - showing that these are double bracketsx2 = 4(x2 - 6x + 9) - expanding the double bracketsx2 = 4x2 - 24x + 36 - multiplying the 4 by the expression inside to remove the brackets0 = 3x2 - 24x + 36 - rearrange to make the equation equal to 00 = x2 - 8x + 12 - realise that there is a common factor of 3 so divide by 3 to simplify the equation0 = (x-6)(x-2) - factorise the expression by finding two numbers that add to (-8) and multiply to make (+12).Finally solve each bracket separately by making them equal to 0 and rearranging for x. x - 6 = 0 so x = 6or x - 2 = 0 so x = 2

Answered by Emily L. Maths tutor

3068 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

These are the selling prices of 5 houses in 2007: £145 000, £170 000, £215 000, £90 000, £180 000. Work out the mean selling price.


Simplify 125 ^ -2/3


Simplify: 5a + 2 – a + 9


How to find the longest side of a right-angled triangle if we are given the two other sides?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences