Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equation by subtracting "3a" from both sides. To leave the "a's" on their own, we subtract "4p" from both sides. We now have the following equation: " - pa - 3a = 5 - 4p". We can factorise the "a" out ending up with "a (-p - 3) = 5 - 4p". To get a alone, we can divide both sides by "(- p - 3). We have now made a the subject: a = (5 - 4p)/ (-p -3).

JP
Answered by Juliana P. Maths tutor

4645 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve simultaneous equations?


Solve x^(2)-x-12


A right-angled triangle has side lengths of 8.65cm and 10.15cm. What is the length of its hypotenuse?


A,B,C and D are points on a circle. ABCD is a square of side 7 cm. Work out the total area of the shaded regions. Give your answer correct to the nearest whole number.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning