Make a the subject of the formula p = (3a + 5)/ (4 - a)

We start by multiplying both sides of the equation by (4 -a). We then expand the brackets "p.(4-a)" and end up with "4p - pa". We then gather the "a's" to one side of the equation by subtracting "3a" from both sides. To leave the "a's" on their own, we subtract "4p" from both sides. We now have the following equation: " - pa - 3a = 5 - 4p". We can factorise the "a" out ending up with "a (-p - 3) = 5 - 4p". To get a alone, we can divide both sides by "(- p - 3). We have now made a the subject: a = (5 - 4p)/ (-p -3).

JP
Answered by Juliana P. Maths tutor

4338 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How to find the roots of a Quadratic Equation by Factorising?


Solve simultaneous equations: 3x + y = 12 and 5x + 5y = 30


In a bag of 72 red and green marbles, 5/9 are green. What is the number of red marbles in the bag?


Given a circle with the equation y^2 + x^2 = 10, with a tangent that intersects at point P, where x=1, find the coordinates for the point at which the tangent meets the x axis (Q).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning