Solve( 3x−2)/4 −(2x+5)/3= (1−x )/6
Firstly, take a common denominator for the left hand-side of the equation which would be 12 and then carrying out the subtraction. After carrying out the subtraction you will be left with two fractions - one on each side of the equation. Subsequently you do cross multiplication and find the value of x from the linear equation which would be 28/3.
3(3x-2)- 4(2x+5)= 2(1-x)9x-6-8x-20=2-2xx+2x=26+23x=28x=28/3 or 9 1/3
WR
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