What is the centre and radius of the circle x^2+y^2-6x+4y=-4

First make left =0x²+y²-6x+4y+4=0Second put same terms together(x²-6x)+(y²+4y)+4=0Complete the Square (do a square (X+b)² that gives you you x² and x terms, repeat with y) these give you the centre values(x-3)²=x²-6x+9(y+2)²=y²+4y+4Put in your completed squares minus the constant value as you only want the x² and x term(x-3)²-9+ (y+2)²-4+4=0Rearrange to get the radius (put constants on right)(x-3)²+ (y+2)²=9Therefore centre (3,-2) radius = sqrt(9)=3