How do I solve simultaneous equations like 2x + 5y = 50 and 3x + y = 23?

With simultaneous equations like these, you first want to get to a point where you have one equation with only one variable. To do this, you must eliminate one of the variables. In this case, if you multiply both sides of the second equation by 5, you get 15x + 5y = 115. Both equations now have a 5y term in them, so you can take one away from the other and eliminate the variable y:
15x + 5y = 115-(2x + 5y = 50)
13x + 0y = 65
65 / 13 = 5, so x = 5. We can now plug this value back into either of the original equations to find y. Using the second equation (before we multiplied it by 5), we get:
3 * 5 + y = 2315 + y = 23y = 8
So x = 5 and y = 8

AH
Answered by Alfie H. Maths tutor

1777 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

find 12% of £550 (non calculator)


An amount of money is split between three people: A, B, and C. C gets 50%, B get 3/9, a) what share does A get. A has £10 b) how much does B have? C spends 90% of his money c) how much total money is left between A, B and C?


If Tom has a bag of balls with 7 orange, 6 green and 11 blue, what is the probability that he will pick a green ball?


Simplify the equation 2x^3 . 3x^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences