Write x^2+6x-7 in the form (x+a)^2+b where a and b are integers
Complete the square.We want a quadratic we can simplify.Halve the linear term coefficient (6) and square it.Add it to the (x2+6x) term and subtract it from the 7.x2+6x+(6/2)2-7-(6/2)2As you can see the equation still holds true as the +(6/2)2 and -(6/2)2 cancels out.Gives x2+6x+9-7-9x2+6x+9 simplifies to (x+3)(x+3) or (x+3)2Left with (x+3)2-16
GB
Related Maths GCSE answers
All answers ▸Solve the following simultaneous equations: 3x + 2y = 16 2x + 3y = 14
Solve these simultaneous equations and find the values of x and y. Equation 1: 2x + y = 7 Equation 2: 3x - y = 8
Complete this substitution question: x^3 - 25 = 103 - x^3
Write √ 45 in the form a √ 5, where a is an integer.