Write x^2+6x-7 in the form (x+a)^2+b where a and b are integers

Complete the square.We want a quadratic we can simplify.Halve the linear term coefficient (6) and square it.Add it to the (x²+6x) term and subtract it from the 7.x²+6x+(6/2)²-7-(6/2)²As you can see the equation still holds true as the +(6/2)² and -(6/2)² cancels out.Gives x²+6x+9-7-9x²+6x+9 simplifies to (x+3)(x+3) or (x+3)²Left with (x+3)²-16