Write x^2+6x-7 in the form (x+a)^2+b where a and b are integers

Complete the square.We want a quadratic we can simplify.Halve the linear term coefficient (6) and square it.Add it to the (x2+6x) term and subtract it from the 7.x2+6x+(6/2)2-7-(6/2)2As you can see the equation still holds true as the +(6/2)2 and -(6/2)2 cancels out.Gives x2+6x+9-7-9x2+6x+9 simplifies to (x+3)(x+3) or (x+3)2Left with (x+3)2-16

Answered by George B. Maths tutor

14902 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The price of a book is 4 pounds. In a sale the price is reduced by 30 percent. Work out the sale price


What is the difference between a histogram and a bar chart? How can I find the frequency density?


Factorise x^2 +6x + 8


How do you solve simultaneous equations.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences