Work out the points of intersection of the graphs of y= (x+2)(x-4) and y=3x+6.
3x+6=(x+2)(x-4)
3x+6 = x2-2x-8
x2-5x-14=0
(x-7)(x+2)=0
x=7 so y=27
and x=-2 so y=0
EL
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