A ball is thrown in the air with velocity of 50.0 m/s, assuming no air resistance calculate its maximum height.
Use SUVAT equations to find height, S, when final velocity, V, is 0: s = ?u = 50 m/sv = 0 m/sa = -9.81 m/st = Not necessaryRecall: v2 = u2 +2as s = -u2/(2a) = -2500/(2 x -9.81) = 127.4 m But given to 3 sig figs so s = 127 m
OG
Related Physics A Level answers
All answers ▸Why do skydivers have a terminal velocity?
A DVD is dropped from rest. The DVD does not reach terminal velocity before it hits the ground. Explain how the acceleration of the DVD varies from the instant it is dropped until just before it hits the ground.
What are the differences between standing waves and progressive waves?
Explain, using appropriate laws of motion, why the air exerts a force on the engine in the forward direction.