A ball is thrown in the air with velocity of 50.0 m/s, assuming no air resistance calculate its maximum height.

Use SUVAT equations to find height, S, when final velocity, V, is 0: s = ?u = 50 m/sv = 0 m/sa = -9.81 m/st = Not necessaryRecall: v2 = u2 +2as s = -u2/(2a) = -2500/(2 x -9.81) = 127.4 m But given to 3 sig figs so s = 127 m

OG
Answered by Oliver G. Physics tutor

1789 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Why are values for gravitational potential always negative?


The speed of water moving through a turbine is 2.5 m/s. Show that the mass of water passing through an area of 500 metres squared in one second is about 1 x 10^6 kg (density of sea water = 1030 kg/m^3)


What's the difference between a bayron and a meson?


How do I solve a problem about a mass on a slide?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences