A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

SE
Answered by Salma E. Further Mathematics tutor

5203 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

If the equation of a curve is x^2 + 9x + 8 = y, then differentiate it.


If y=(x^2)*(x-10), work out dy/dx


Simplify fully the expression ( 7x^2 + 14x ) / ( 2x + 4 )


Work out the equation of the tangent to the curve y=x^2+5x-8 at the point (2,6)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences