A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.
The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4
SE
Answered by Salma E. • Further Mathematics tutor
6366 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Find the stationary point of 3x^2+7x
What is differentiation used for?
If y=x^3+9x, find gradient of the tangent at (2,1).
x^3 + 2x^2 - 9x - 18 = (x^2 - a^2)(x + b) where a,b are integers. Work out the three linear factors of x^3 + 2x^2 - 9x - 18. (Note: x^3 indicates x cubed and x^2 indicates x squared).