A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

SE

Related Further Mathematics GCSE answers

All answers ▸

How do I determine if a stationary point on a curve is the maximum or minimum?


A=(1,a;0,1/2) B=(1,-1;0,2) AB=I, calculate the value of a.


Find the coordinates of any stationary points of the curve y(x)=x^3-3x^2+3x+2


Find the definite integral of f(x) = 12/(x^2+10x+21) with limits [-1,1]. Give your answer to 2 decimal places.