A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

Related Further Mathematics GCSE answers

All answers ▸

Find and describe the stationary points of the curve y = x^2 + 2x - 8


How do I know I can multiply two matrices and if so, how do I do it?


y=(6x^9 +x^8)/(2x^4), work out the value of d^2y/dx^2 when x=0.5


Solve these simultaneous equations: 3xy = 1, and y = 12x + 3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences