Find and describe the stationary points of the curve y = x^2 + 2x - 8

Stationary points occur when the derivative is = 0Derivative: 2x + 2 = 0, so a stationary point occurs when x = -1y = 1 + 2 - 8 = -5Second derivative = 2Therefore, the stationary point (-1,2) is a minimum

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Point A lies on the curve: y=x^2+5*x+8. The x-coordinate of A is -4. What is the equation of the normal to the curve at A?


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