This is a simultaneous equations question. In this situation the equations can be multiplied to create a common coefficient: 3x+y=11 therefore 6x+2y=22You can then add the equations together: 6x+2y=22 plus 5x-2y=11 therefore 11x=33 and x=3Subbing x=3 into one of the initial equations allows you to solve for y:3x+y=11 therefore 3(3)+y=11 therefore 9+y=11 therefore y=2Check these answers by substituting x and y into the other equation: 5(3)-2(2)=15-4=11Therefore x=3 and y=2