Solve the Simultaneous equations. 3x+5y=22 4x-5y=6

3x+5y=224x-5y=6Our first task is to cancel out one of the variables. So you see that both y variables have a 5 before them. As one has -5 and the other has +5 you can add both simultaneous equations together to cancel out the y's. this gives us the result:7x +0y = 28 -> 7x=28. Then to find the value of "x" we divide both sides by 7 giving us x = 4. Then to find out the value of y we substitute the value of x back into either of the equations. Lets choose 3x+5y=22. Subbing in x=4 gives us 3*4+5y=22 -> 12+5y=22. Subtracting 12 from both sides gives 5y = 10. Then dividing both sides by 5 gives y = 2. Therfore the solution to these equations is x=4 and y=2

Answered by Chris L. Maths tutor

3223 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the roots of the following equation 2x^2-11x+14=0


Fully expand (2x+4)(4x-3).


If 11 carrots weigh 170g how much would 20 carrots weigh?


A linear sequence begins: a + 2b, a + 6b, a + 10b, ..., ... Given that the 2nd term has a value of 8 and the 5th term has a value of 44, calculate the values for a and b


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences