A curve has the equation x^2 +2x(y)^2 + y =4 . Find the expression dy/dx in terms of x and y [6]

Integrate each term in terms of x, then integrate each term in terms of y Make sure you state in what form you are integrating. Remember if you are integration in terms of y, the x values are constants and vice versa 2x + 2(y^2) + (2x*2y)dy/dx + 1dy/dx = 0 2x + 2(y^2) + (4xy +1) dy/dx = 0 [4](4xy +1) dy/dx = -(2x + 2(y^2) )Therefore dy/dx = -(2x + 2(y^2) ) / (4xy +1) [2]

Answered by Lavana C. Maths tutor

3197 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the tangent to curve y=5x^2-2x+3 at the point x=0


how can differentiate using the product and chain rule? e.g y=(4x+1)^3(sin2x), find dy/dx.


Let f(x)=xln(x)-x. Find f'(x). Hence or otherwise, evaluate the integral of ln(x^3) between 1 and e.


Find the differential of (cos2x)^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences