A curve has the equation x^2 +2x(y)^2 + y =4 . Find the expression dy/dx in terms of x and y [6]

Integrate each term in terms of x, then integrate each term in terms of y Make sure you state in what form you are integrating. Remember if you are integration in terms of y, the x values are constants and vice versa 2x + 2(y^2) + (2x*2y)dy/dx + 1dy/dx = 0 2x + 2(y^2) + (4xy +1) dy/dx = 0 [4](4xy +1) dy/dx = -(2x + 2(y^2) )Therefore dy/dx = -(2x + 2(y^2) ) / (4xy +1) [2]

LC
Answered by Lavana C. Maths tutor

3763 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate sin^2(3x)cos^3(3x) dx?


A curve C has equation: y = x^2 − 2x − 24x^1/2, x > 0; Find (i) dy/dx (ii) d^2y/dx^2


State the interval for which sin x is a decreasing function for 0⁰ ≤ x ≤ 360⁰.


How do I write the function 3cosθ+4sinθ in the form Rsin(θ + α), where R and α are positive constants?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning