How do I find the dot product of two 3-dimensional vectors

Example; Let vector v = (2,5,2) and vector u = (1,-2,3),then u Β· v = [(2 x 1) + (5 x -2) + (2 x 3)] = [2 -10 + 6] = -2 As the workings hopefully make clear in the line above, the general formula for the scalar product of vectors a and b (if a = (x1,y1,z1) and b = (x2,y2,z2)) is π’‚βˆ™π’ƒ=(𝒙1𝒙2+ π’š1π’š2+𝒛1𝒛2). The same holds true if the vectors are represented as column vectors. If the angle between two vectors is known, it is also possible to calculate the scalar product using the equation: π’–βˆ™π’—=𝑼𝑽𝒄𝒐𝒔(𝜽) where U and V are the magnitudes of u and v and 𝜽 is the angle between the vectors. *Note, the scalar product of two perpendicular vectors is 0 as cos(90Β°)=0

Answered by Theo V. β€’ Maths tutor

985 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers β–Έ

Differentiate (x-2)^2


Given that, dy/dx = 6x^2 - 3x + 4, and y = 14 when x = 2, express y in terms of x.


Solve algebraically the following system of equations: 4x + 5y = -3; 6x - 2y = 5


Show that (π‘₯ βˆ’ 1) is a factor of 𝑓(π‘₯)=2π‘₯^3 + π‘₯^2 βˆ’ 8π‘₯+ 5. Hence fully factorise 𝑓(π‘₯) fully.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

Β© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy|Cookie Preferences
Cookie Preferences