The equation of line A is (x)^2 + 11x + 12 = y - 4, while the equation of line B is x - 6 = y + 2. Find the co-ordinate(s) of the point at which lines A and B intersect.

While this question may seem complicated, this question is simply asking you to solve the equations of these two lines as simultaneous equations. Line A: x2 + 11x + 12 = y - 4 --> x2 + 11x + 16 = y; Line B: x - 6 = y + 2 --> x - 8 = y. At the co-ordinate(s) at which lines A and B intersect, x2 + 11x + 16 = x - 8. If you bring all the x's in the equation above to the same side: x2 + 10x + 24 = 0, which can also be written as: (x + 6)(x + 4) = 0. Solving this equation for x: x + 6 = 0 (x = - 6) AND x + 4 = 0 (x = - 4)When x = - 6, y = (- 6) - 8 = - 14 AND when x = - 4, y = (- 4) - 8 = - 12... Therefore lines A and B cross at two points: (- 6, -14) and (-4, -12)

AA
Answered by Ann A. Maths tutor

2787 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

solve y=3x+4, x=y+1


Simplify fully: (7x^2 - 21x)/(x^2 + 2x - 15)


There are n sweets in a bag. 6 of the sweets are orange. The rest of the sweets are yellow. Hannah takes a sweet from the bag and eats it. Hannah then takes at another sweet. The probability that Hannah eats two orange sweets is 1/3. Show that n²-n-90=0


A level - Find the coordinates of the stationary point of the curve with equation : (x+y-2)^2 + e^y -1


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences