Calculate the rate of change of d(t )=2/(3t), t ≠ 0, when t=6.

When a question asks for rate of change, this means you need to differentiate the equation. First you need to put the equation into differentiable a form ie, with the no variables on the denominator: f(t) = 2/3t^-1Then you can differentiate by multiplying the coefficient by the power and then reducing the power by one: f'(t)= -2/3t^-2We can put this back to a standard form to make it easier to work with: f'(t) = -2/(3t^2)Substitute t = 6 in and we get: f-(t) = -2/(3*36) = -2/108 = -1/54

LI
Answered by Lucy I. Maths tutor

2543 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

a) Factorise: 2x^2-72, and hence b) find the y-intercept of the line with the equation: y=(2x^2-72)/(4x-24)


A circle has equation x^2+y^2+6x+10y-7=0. Find the equation of the tangent line through the point on the circle (-8,-1).


y=x^3-3x^2+2x+5 a)Write down the coordinates of P the point where the curve crosses the x-axis. b)Determine the equation of the tangent to the curve at P. c)Find the coordinates of Q, the point where this tangent meets the curve again.


Solve algebraically the system of equations: 4x+5y=-3 and 6x-2y=5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning