Differentiate: y=x^x

First take log’s each side as it would turn our complicated function into something differentiable by chain rule.
ln y = x*ln x
Then differentiate y with respect to x:
d(ln y)/dx = ln x + 1
1/y * dy/dx = ln x +1
dy/dx = y(ln x +1)
As we know what y is the final result is dy/dx= x^x(ln x +1)

Related Further Mathematics A Level answers

All answers ▸

Find the volume of revolution formed by rotating the curve y = sinx 2pie around the x- axis


Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form


Why does e^ix = cos(x) + isin(x)


Prove by induction that, for all integers n >=1 , ∑(from r=1 to n) r(2r−1)(3r−1)=(n/6)(n+1)(9n^2 -n−2). Assume that 9(k+1)^2 -(k+1)-2=9k^2 +17k+6


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences