The kinetic energy of the moving car will be converted to gravitational potential energy as it travels up the ramp. At the point that the car will jump, KE = GPE therefore 1/2 mv^2 = mgh. Therefore, when we manipulate it, if v^2 > 2gh, the car will jump.Putting in numbers: is 3^2>29.80.5? 9 is not greater than 9.8 so the car will not jump.