How would I go about finding the coordinates minimum point on the curve eg y = e^(x) - 9x -5?

In order to find the coordinates of the minimum point of any curve y = f(x), you must differentiate the equation of the curve with respect to x and then equate it to zero.In this case, the differential of the curve is: dy/dx = e^(x) - 9
Equating this to zero you find that e^x = 9.
Therefore x = ln(9)
Substituting this back int the original equation for the curve to find y: y= e^(ln(9)) - 9ln(9) - 5 , noticing that the e^ ln cancel out.
Thus, x = ln(9) and y = 9-5 - 9ln(9) = 4 - 9ln(9)

Answered by Theo R. Maths tutor

2983 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How can the y=sin(x) graph be manipulated?


Solve, giving your answer to 3 s.f. : 2^(2x) - 6(2^(x) ) + 5 = 0


Find the cartesian equation of a curve?


Express (9x^2 + 43x + 8)/(3+x)(1-x)(2x+1) in partial fractions.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences