The y-intercept of A is 7. A also passes through point (7, 2). (a) Find an equation of A in the form y = mx + c. (b) B is perpendicular to A and also has a y-intercept of 7. Write down the equation for B in the form y = mx + c.

(a) y-intercept = (0,7); other point = (7,2) ; gradient, m = change in y / change in x ; m = (0 - 7) / (7 - 2) => m = -7/5 ; y = mx + c (we know from the question that c=7) ; y = (-7/5)x + 7(b) gradient of B is -1/(-7/5) = 5 / 7 ; y = (5/7)x + 7

Answered by Oliver T. Maths tutor

2362 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following simultaneous equations: 4x+y=10 and 2x-3y=19


If 4x = 9y, and 2x + 5y = 95. What is the value of y^2 - x?


Rationalise the denominator of 1/(4 + sqrt(3))


A right-angled triangle has two smaller sides of length 5cm and 12cm. What is the length of the hypotenuse?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences