Find the point of intersection between the lines 2y=-4x+4 and 3y=10x-3

The easiest way to find the point of intersection between two lines is to use simultaneous equations. Begin by setting y=y or x=x. In this case we will be setting y=y, in order to do this you must manipulate the equations such that the multiplier of both of the y values is the same.
We will begin by multiplying the first equation (2y=-4x+4) by 3 which gives us
6y=-12x+12
We then multiply the second equation (3y=10x-3) by 2 which gives us
6y=20x-6
now we can set these equations equal to each other because at the point of intersection the y value of each line will be the same, therefore since y=y, 6y=6y and it then follows
-12x+12=20x-6
We can then solve this equation for
x=1/2
now that we know the x value at the point of intersection we simply choose one of the equations (preferably the simplest) and input the x value we found into that equation, this will then give us our y value.
3y=10x-3
3y=5-3
y=2/3
Thus the point of intersection is (1/2, 2/3)

Answered by Scott S. Maths tutor

2537 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that the difference between the squares of any two consecutive integers is equal to the sum of these two integers.


Show that the lines y=3x+7 and 2y–6x=8 are parallel. Do not use a graphical method.


Square root of 81?


Solve the following simultaneous equations: 1) 2x + 7y = 12 2) 4x = 14 - 4y


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences