Solve simultaneously 2x+3y=8, 3x+2y=7 to calculate values of x and y.

First of all, we must multiply each equation by a suitable number in order to get the same leading coefficient. In simple terms, we must make the coefficient of the x or the y in both equations the same. So here it is easy to multiply the first equation by 3 to get 6x+9y=24 and the second by 2 which gives us 6x+4y=14. Now if we subtract equation 1 by equation 2, we have 5y=10. To make y the subject, we must divide both sides by 5 which gives us y=2.Let us substitute this value of y into 2x+3y=8. We have 2x+(3*2)=8. Again if we rearrange this for x, we have x=1.

VL
Answered by Vasant L. Maths tutor

5637 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

An isosceles triangle ABC has a perimeter of 16cm. AB = x+3, AC = x+4. Calculate the area of ABC.


Solve the simultaneous equations (1) 2x+3y=3 and (2) 3x+2y=7


Rearrange the equation y=3x+2 to make x the subject.


Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences