Solve the simultaneous equations: 6x - 5y = 17, 3x + 8y = 10

First, you will need to make one of the variables x or y have the same number in front. To do this just multiply the equation by a constant which will give you lets say the x value in this equation with the same constant in both equations. The lowest common multiple of 6 and 3 is 6. So the first equation remains the same and the second equation is multiplied by 2 to result in 6x + 16y = 20. Now the equations can be subtracted by each other to get rid of the x value and allow you to solve for y. This will result in (6x - 6x) + (16y--5y) = (20-17) . Leaving you with 21y = 3.To get the value for y just divide 3 by 21 which will give you the fraction 1/7 for y and plug this into any of the original equations to solve for x, which will give you 6x -5*(1/7) = 17. Rearrange to give 6x = 124/7. x = (124/7)/6 = 62/21.

JS
Answered by Jagjit S. Maths tutor

3839 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

In a group of 120 people, 85 have black hair, 78 have brown eyes and 20 have neither black hair nor brown eyes. Find the probability of a random person being picked having black hair, given they have brown eyes


For the equation, 5(7x + 8) + 3(2x + b) ≡ ax + 13. Find the values of a and b. You may use a calculator.


Probabilities: "A bag contains counters that are red, blue, green and yellow. There are 9 red, (3x) blue, (x-5) green and (2x) yellow. If the probability of picking a red at random is 9/100, work out the probability of picking a green."


What is 17 multiplied by 120?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences