Using the diagram and your knowledge of vectors, show that BCD is a straight line

BC = BA - CA = (3a - b) - (a + 4b) = 2a - 5b BD = BA + AB = (3a - b) + (a - 9b) = 4a - 10b BC = 1/2 BD. Using basic vector rules, we know that if vectors are multiples, then they are parallel. Since BC and BD start at the same point, we can deduce that they are on a straight line. Points lying on a straight line are known as collinear and BC and BD are scalar multiples of each other.

JA
Answered by Jonathan A. Maths tutor

15771 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A "day return" train ticket is £6.45. A "monthly saver" is £98.50. Sue worked for 18 days last month. She bought a day return ticket each day she worked. A monthly saver ticket is cheaper than 18 day return tickets. How much cheaper?


Factorise fully 8y + 4y^2


How to solve problems with discount applied twice in the same product?


c is a positive integer. Prove that (6c^3+30c) / ( 3c^2 +15) is an even number.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences