How do we differentiate y = arctan(x)?

Step 1: Rearrange y = arctan(x) as tan(y) = x.

Step 2: Use implicit differentiation to differentiate this with respect to x, which gives us:

(dy/dx)*(sec(y))^2 = 1.

Step 3: Rearrange this equation to give us:

dy/dx = 1/(sec(y))^2.

Step 4: Use a trigonometric identity to substitute and find that:

dy/dx = 1/(1+((tan(y))^2).

Step 5: Recall that x = tan(y) and substitute this to find: 

dy/dx = 1/(1+x^2).

Done.

SC
Answered by Solly C. Maths tutor

82203 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that (2x + 11 )/(2x + 1)(x + 3) ≡ A /(2x + 1) + B /(x + 3) , find the values of the constants A and B. Hence show that the integral from 0 to 2 (2x + 11)/ (2x + 1)(x + 3) dx = ln 15.


Find the gradient of y=6x^3+2x^2 at (1,1)


Differentiate y=sin(x)*x^2.


Factorise x^3+3x^2-x-3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning