The answer to this question is in two parts. We firstly must find the derivative of the function y=f(x) with respect to x, and then substitute the value of x given in the question to find the gradient at that point.To find the derivative of the function, we use both the product and chain rule. we see that dy/dx =4xe^2x+2e^2x using these rules for differentiation.we now substitute x=1 into this to find the gradient as 6e^2 at this point.