Cube roots of 8?

8 traditionally has 1 cube root. 2. This is only the real root. It has 2 more complex roots!How can we see this?Consider a vector on the argand diagram. If we square it. What happens to it's magnitude and arguement?So as we can see. If 8 is expressed on an argand diagram. The vector at 2 when cubed maps to 8. But can you see the two other points?In general the nth cube root of a complex number has n roots.

VJ

Related Further Mathematics A Level answers

All answers ▸

What is De Moivre's theorem?


Show that the points on an Argand diagram that represent the roots of ((z+1)/z)^6 = 1 lie on a straight line.


Find the determinant of a 3x3 matrix.


z = 4 /(1+ i) Find, in the form a + i b where a, b belong to R, (a) z, (b) z^2. Given that z is a complex root of the quadratic equation x^2 + px + q = 0, where p and q are real integers, (c) find the value of p and the value of q.