Why is |z| = 1 a circle of radius one? (FP2)

So, basically |z| = 1 is equal to the set containing all complex numbers where their magnitude is equal to one. Also, by unraveling the definition of |z| we get that (x2+y2)1/2=1 which is the same as x2+y2=1 which we can identify as the circle with centred at (0,0) and radius 1.

CM
Answered by Charalambos M. Maths tutor

3728 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve with equation y=f(x) passes through the point (1, 4/3). Given that f'(x) = x^3 + 2*x^0.5 + 8, find f(x).


How would you integrate ln x


How do I integrate x/(x^2 + 3) ?


y=e^2x-11e^x+24 Find the stationary point, nature of the stationary point, the x-intercepts and the y-intercept (calculator allowed)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning