y = x^2 − 2*x − 24*sqrt(x) - i) find dy/dx ii) find d^2y/dx^2

Solved by differentiation with respect to x,i) dy/dx = 2x - 2 - 12x^(-1/2)ii) d^2y/dx^2 = 2 + 6*x^(-3/2)

DG

Related Maths A Level answers

All answers ▸

using the substitution u=6-x^2 integrate (x^3)/(6-x^2)^1/2 with respect to x, between 1 and 2


How do I differentiate (e^(2x)+1)^3?


Why does ln(x) differentiate to 1/x ?


The equation of a curve is xy^2= x^2 +1. Find dx/dy in terms of x and y, and hence find the coordinates of the stationary points on the curve.