A trolley of negilible mass on horizontal tracks is at rest. A person of mass 50kg is standing on the trolley with a bag of mass 10kg. The person throws the bag off the trolley horizontally with a velocity of 3m/s. Calculate the velocity of the man.
Establish what information you have been given in the question (mass of person=50kg, mass of bag=10kg, velocity of bag=3m/s, start velocity of both=0m/s). Use the equation momentum=mv and the principle of conservation of momentum. This means that the initial momentum of the man and bag is 0 as they are stationary. Therefore mass of bag * 3 = mass of man * v. Solve for v to get 0.6m/s.
EC
Related Maths A Level answers
All answers ▸How would you integrate ln(x) with respect to x?
differentiate the following equation: y = x^2 + 2x
A tank is filled with water up to the height H0. At the bottom of the tank, there is a tap which is opened at t=0. How does the height of liquid change with time?(Hint: dH/dt is proportional to -H)
Differentiate f(x) = (3x + 5)(4x - 7)