A trolley of negilible mass on horizontal tracks is at rest. A person of mass 50kg is standing on the trolley with a bag of mass 10kg. The person throws the bag off the trolley horizontally with a velocity of 3m/s. Calculate the velocity of the man.

Establish what information you have been given in the question (mass of person=50kg, mass of bag=10kg, velocity of bag=3m/s, start velocity of both=0m/s). Use the equation momentum=mv and the principle of conservation of momentum. This means that the initial momentum of the man and bag is 0 as they are stationary. Therefore mass of bag * 3 = mass of man * v. Solve for v to get 0.6m/s.

Answered by Ella C. Maths tutor

2801 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The variable x=t^2 and the variable y=2t. What is dy/dx in terms of t?


Express root(125^x)/5^(2x-1) in terms of 5^a where a is an expression in terms of x.


The curve y = 4x^2 + a/x +5 has a stationary point. Find the value of the positive constant 'a' given that the y-coordinate of the stationary point is 32. (OCR C1 2016)


Express cos(2x) in terms of acos^2(x) + b


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences