Rearrange the following to make c the subject: 11a + 5c = d ( 6 + 2c )

Steps: (1) Multiply out the brackets on the left handside [11a + 5c = 6d + 2dc]. (2) Put all terms containing c on one side and all other terms on the other side of the equation [ 5c - 2dc = 6d - 11a]. (3) Take c as a factor from the terms that contain c [c(5 - 2d ) = 6d - 11a] (4) Divide through to isolate c by itself [c = (6d - 11a) / (5 - 2d)]

Answered by Jeremy L. Maths tutor

3186 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Express 216 as a product of its prime factors.


Solve this pair of simultaneous equations (1) 5x+2y=20 and (2) x+4y=13


Factorise x^2 + 3x +2


Solve the following simulateous equations: 3x+y=11 and 2x+y=8


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences