Rearrange the following to make c the subject: 11a + 5c = d ( 6 + 2c )

Steps: (1) Multiply out the brackets on the left handside [11a + 5c = 6d + 2dc]. (2) Put all terms containing c on one side and all other terms on the other side of the equation [ 5c - 2dc = 6d - 11a]. (3) Take c as a factor from the terms that contain c [c(5 - 2d ) = 6d - 11a] (4) Divide through to isolate c by itself [c = (6d - 11a) / (5 - 2d)]

Answered by Jeremy L. Maths tutor

3121 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify √90+√360+5√10


Solve the simultaneous equations 4x + 5y = 13 and 3x - 2y = 27.


Part 1 of a test has 60 marks, Part 2 has 100 marks. James scores 75% on part 1 and 48% on part 2. To pass the full test, he needs 60% of the total marks, does he pass?


How do you work out the gradient of a straight line?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences