24 g of Magnesium reacts with 16 g of Oxygen to produce 40 g of magnesium oxide. What mass of magnesium would you need to produce 10 g of magnesium oxide?

There are two ways to work this out, one is a lot simpler than the other, I will post the simpler method here.

The relative formula mass of magnesium oxide, MgO (40), is just a sum of the mass of magnesium (24) and the mass of oxygen (16).

24 + 16 = 40

We are told that 24 g of Mg produces 40 g of MgO when it reacts with 16 g of oxygen. We only need 10 g of MgO, 1 quarter of that given in the question.

In order to produce 10 g of MgO, we therefore only need a quarter of what we needed to make 40 g of MgO.

So, we would only need 24 g / 4 = 6 g of Mg to produce 10 g of MgO.

Answered by Joshua H. Chemistry tutor

64459 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

What are the differences between the effects of a catalyst vs reactant concentration on the position of equilibrium/ why?


What is the difference between atom economy and percentage yield?


What is an isotope?


What are covalent and Ionic bonds and how do they differ?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences