Expand the brackets: (3a+3)(a+4)

To expand this, we must multiply each term in both brackets separately and then add all of these terms together. First, multiply the first term in each of the brackets: 3a x a = 3a^2. Next multiply the first term in the first bracket by the second term in the second brackets: 3a x 4 = 12a. Next multiply the second term in the first brackets by the first term in the second: a x 4 = 4a. Lastly, multiply the second term in each of the brackets: 3 x 4 = 12. Now add these all up to get: 3a^2 + 12a + 4a + 12 = 3a^2 + 16a + 12

LB
Answered by Luke B. Maths tutor

4119 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the equation x^{2}-2x-15 = 0


In one month, Karen takes the bus to school on 25 days. On 5 of these days the bus is late. What fraction of the days Karen takes the bus to school is the bus late? (Give your answer in the simplest form)


If side A is 3m and side B is 4m, what would be the length of the remaining side C?


Solve the simultaneous equations: 5x + y = 21 and x - 3y = 9


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning