Answers>Maths>IB>Article

Differentiate, from first principles, y=x^2

According to first principles, the differential is found as the limit as h->0 of:[f(x+h)-f(x)] / hif we set our f to x^2, then we find that this expression becomes (x^2+2hx+h^2 - x^2)/hWhich simplifies to 2x+h. As h->0, this leaves us with 2x, which is the derivative of x^2

Answered by Milo E. Maths tutor

1804 Views

See similar Maths IB tutors

Related Maths IB answers

All answers ▸

The sum of the first and third term of a geometric sequence is 72. The sum to infinity of this sequence is 360, find the possible values of the common ratio, r.


log8(5) = b. Express log4(10) in terms of b


Find the first and second order derivative of the function, F(x)= 3x^3 - 7 + 5x^2, and then identify the maximum or minimum points.


If f(x)=(x^3−2x)^5 , find f'(x).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences