Differentiate y = (3x − 2)^4

We recognise that this is in the form of a function within a function, i.e u= 3x - 2 is within the u^4 function, therefore here we will use the chan rule to differentiate the equation. 

The chain rule states that dy/dx = dy/du * du/dx.

Here let u = 3x -2, then du/dx = 3. Similarly, y=u^4 so dy/du = 4u^3. Therefore dy/dx = 3 * 4u^3 = 12u^3.

Finally, we substitute u = 3x - 2 into the equation. This therefore gives us, dy/dx = 12(3x - 2)^3.

WI
Answered by Wajiha I. Maths tutor

15404 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate sin(x)*x^2


How would I solve the equation 25^x = 5^(4x+1)?


Find the turning point of the function y=f(x)=x^2+4x+4 and state wether it is a minimum or maximum value.


Express X/((X+1)(X+2)) in partial fractions. OCR C4 style question


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences