A particle of mass 5kg is acted upon by a force of 400N for a distance of 20m along the x axis. What is its final velocity if it is initally at rest?

The work done by a force on a particle is: Work done = Force x Displacement.The energy of a particle is given by the sum of its potential and kinetic energies.As the particle does not gain or lose any height (in the y axis), only its kinetic energy changes.Therrfore the work done by the force is 400(N) x 20(m) = 8000(J).This is equal to its change in kinetic energy = 0.5 x m x v2 . = 0.5 x 5 x v2.By algebra: sqrt(2x8000/5) = v = 56.6ms-1.

Answered by Luke T. Physics tutor

1608 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

A car accelerates (at a constant acceleration) from a velocity of 25m/s to 34m/s in 6s. Calculate the cars acceleration.


What is the difference between acceleration, speed and velocity?


Waves on the surface of water are transverse waves. State one other example of a transverse wave.


What is the density of a rock (mass 75g) submerged in water which displaced by a volume of 37.5cm^3? SI units


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences