Solve the following set of equations. 3x + 2y = 5, 2x + 3y =6

This question is an example of simultaneous equations. It's very important to show your working on this question otherwise you won't get any marks, even if you get the right answer! All simultaneous questions you will come across will have more or less the same approach. We want to start off by removing one of the variable from the equations. We do this by adding /subtracting a multiple of one of the equations to the other. Let's label the first equations a, and the second equation b - to make it easy to see for the marker what we are doing. Now if we calculate 2a-3b we get 6x + 4y - 6x -9y = 10-18.Which simplifys to -5y= -8. And so we get y = (-8/-5) =8/5. We now substitute this value of y into equation a: 3x + 16/5 = 5. We then get 3x = 5-16/5 =9/5. So x = 3/5.It is often good to try your values in both equations to check if your answers are correct.

Answered by Errol L. Maths tutor

3373 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Make x the subject 2x+3=3x-1


Work out the increase in price from £1.50 to £2.00 as a percentage.


Solve the equation ((2x+3)/(x-4))-((2x-8)/(2x+1)) = 1 to 2 decimal places.


Solve algebraically: 1) 6a + b = 16, 2) 5a - 2b = 19


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences