Solve the following set of equations. 3x + 2y = 5, 2x + 3y =6

This question is an example of simultaneous equations. It's very important to show your working on this question otherwise you won't get any marks, even if you get the right answer! All simultaneous questions you will come across will have more or less the same approach. We want to start off by removing one of the variable from the equations. We do this by adding /subtracting a multiple of one of the equations to the other. Let's label the first equations a, and the second equation b - to make it easy to see for the marker what we are doing. Now if we calculate 2a-3b we get 6x + 4y - 6x -9y = 10-18.Which simplifys to -5y= -8. And so we get y = (-8/-5) =8/5. We now substitute this value of y into equation a: 3x + 16/5 = 5. We then get 3x = 5-16/5 =9/5. So x = 3/5.It is often good to try your values in both equations to check if your answers are correct.

Answered by Errol L. Maths tutor

3429 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How can graphs be used in solving equations?


There is a right angled triangle, you know the length of the hypotenuse (6) and one other side (3), can you calculate the third side of the triangle?


Find the values of X and Y from the simultaneous equations: 1) 2x + 5y = 33 2) x + 3y = 19


ABC and BCD are two attached triangles, attached along line BC. AB = 5.8cm, AC=5.2cm, BD=4.3cm. Angle BDC = 30 degrees, and angle DCB is a right angle. Calculate angle CBA.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences