Find the positive solution to the equation (x^2+9x+18)/(x^2-9)=10

If we first factorise the top and the bottom of the equation we can see that the top is equal to (x+6)(x+3) and the bottom is (x-3)(x+3). This means we can divide the top and bottom by (x+3) giving us a result of x=-3 which is negative so is not the required solution. However, we are then left with (x+6)/(x-3)=10 which can be rearranged to give (x+6)=10(x-3) and then expanded to give us x+6=10x-30. Rearranging again we get to 9x=36 and then dividing through by 9 we get x=4 which is a positive solution, as required.

Answered by Joseph R. Maths tutor

2424 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 5 – 10m


Solve 9x-4=7(x+2)


(a)Show that the lines y=3x+7 and 2y–6x=8 are parallel. [3 marks] (b) Is the point (–5, –6) above, below or on the line y = 3x + 7 ? Do not use a graphical method. [2 marks] [Total 5 marks]


What are the roots of the graph of this equation: x^2 + 9x + 18 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences