let line L have the equation 4y -3x =10, and line M passes through the points (5,-1) and (-1,8), find out if they are perpendicular, parallel, or neither

L:4y=3x+10 -> y=3/4 x + 10/3. M: y= mx+ c such that it passes through the points in question, then m=(-1-8)/(5-(-1))=-3/2. As the gradient of L is not a negative reciprocal of the gradient of M, nor is it equal to the gradient of M, they are not parallel, nor perpendicular

Answered by Illya N. Maths tutor

3965 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

y = 4x / (x^2 + 5). Find dy/dx.


The curve C has equation y=3x^3-11x+1/2. The point P has coordinates (1, 3) and lies on C . Find the equation of the tangent to C at P.


Let w, z be complex numbers. Show that |wz|=|w||z|, and using the fact that x=|x|e^{arg(x)i}, show further that arg(wz)=arg(w)+arg(z) where |.| is the absolute value and arg(.) is the angle (in polar coordinates). Hence, find all solutions to x^n=1 .


How do I use the product rule for differentiation?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences