Find the gradient at the point (0, ln 2) on the curve with equation e^2y = 5 − e^−x . [4]

Figure out what skills are being tested: implicit differentiation and exponentials and logarithms.e2y = 5 - e-x2e2y(dy/dx) = e-x(dy/dx) = e-x/ 2e2yAt (0, ln2) (dy/dx) = e0 / 2e2ln2 e2ln2 = 4 as 2ln2 = ln(22) and eln(x)= x (dy/dx) = 1 / 8.

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