Find the minimum value of the function, f(x)= x^2 + 5x + 2, where x belongs to the set of Real numbers

We first differentiate f(x), and we get f'(x)=2x + 5. We then set this equal to 0 and then solve for x. We get that xmin= -2.5. We check whether this was indeed a minimum, by calculating the second derivative, f''(xmin)= 2. Since f''(x) > 0 we know that xmin is indeed a (local) minimum. Then to find the minimum value of f(x), we substitute the value of x back to the equation and get the minimum value of f(x) is -4.25 ((-2.5)^2 + 5(-2.5) + 2 = -4.25))

Answered by Pavlos P. Maths tutor

3064 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How can you integrate the function (5x - 1)/(x^(3)-x)?


y = (x^2)sin(3x). Find dy/dx


Using integration by parts, and given f(x) = 3xcos(x), find integrate(f(x) dx) between (pi/2) and 0.


How does a hypothesis test work?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences